Posts+10-27-14

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FYI, Calc Class--

I think everything looks really great! Nice posts! As far as I could tell, we had all the correct answers. If you see one that isn't correct, please let me know. Or better yet, fix it! :)

The only one that is left to post is #61 (I think), so all others I can vouch for their correctness (is that a word?). Follow?

jn



Jace H #4

Mike W #7

First, I switched the first square roots of x to x raised to the 1/2 power. Then, I switched the 1/square root of x to x raised to the negative 1/2 power. Finally, I found the derivative of the problem.

Ivy O - #5 First, I look at the given equation and figure out what rule would apply to finding the derivative. Since there is multiplication involved, I figured out that Product Rule would be the necessary rule to use in this case. Second, I defined my terms and used Power Rule to find the derivatives of the terms. Next, I put my terms into Product Rule format and set it equal to s’. Then, I distributed and simplified. After that, I was able to cancel some terms and simply to find my answer.

Rachel Schartz - #9

Teddy M #10 She meant to say "foiled" or "distributed" instead of "factored". :)

Nasya S #11

Lauren D #13

Conner U #14

Austin K #17

Brandon G #25


 * 1) 45 Janell H

First, I found the derivative of the original problem. Next, after you found the derivative, plug the valve given (2) into x in the derivative. This answer will be your slope. To find the “Y” value for your equation, plug x=2 into the original problem to find the “y” value. Use the equation Y1-Y2=m(X1-X2) Plug your values into the equation. y-2=-2(x-2) (this is your tangent line) To find the normal line, find the negative reciprocal of the slope from the tangent line. Use the same equation to find the normal line. y-2=1/2(x-2)

Jared B #43

I used the power rule to arrive at each derivative.

FYI: The first term's derivative isn't quite right. From the x^4/2, you should get the derivative to be 2x^3. Good catch, Janell!

Anna B #47

Paige H #53

Carson U., p. 148, #55



Maddi M #33

Chase H - #35

Hanna W 68a&b



Great post, Hanna! I think you accidentally did a little math in your head while you were working. :) Part b should be y'=(-1)(4)+(-3)(-2)=2. Otherwise, all good!

Will L #72a

First I set s=490t^2 equal to the height which was 160cm, then you solve the equation, you should get 4/7 sec. For the next part of the probelm I found the average velocity by entering the time period [0-4/7] it into the f(B)-f(A)/B-A equation. You should end up with 280 cm/s.

Trevour Eldredge #72b

// First, use the power rule to find the derivative of each term in the equation. // // Next, combine all of the derivatives into one equation and set them equal to x’(t). //
 * 1) 81. a. Keagan P

// Noah F #81b // First, find the derivative of the beginning equation - this is velocity. The easiest way is to use the power rule! Then find the derivative of the velocity - this is acceleration. Good catch, Bella! The x" answer should have been 6t. I had even missed that yesterday when I was checking things. Thanks, Bella, for catching that!

Seth T #81c

// Drue M #81d // First I found the derivative of the distance function to get the velocity formula. Then I found the derivative of the velocity function to get the acceleration formula. Next I plugged in zero for acceleration to find the time at which acceleration is zero. After I found the time to be zero, I plugged the zero time into my velocity function. Finally, solving for velocity I got -12. Since I was finding speed I needed to find the absolute value of velocity. Speed ended up being 12. Izzy M #81e